3x/2-x-7=2x^2+5

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Solution for 3x/2-x-7=2x^2+5 equation:



3x/2-x-7=2x^2+5
We move all terms to the left:
3x/2-x-7-(2x^2+5)=0
We add all the numbers together, and all the variables
-1x+3x/2-(2x^2+5)-7=0
We get rid of parentheses
-2x^2-1x+3x/2-5-7=0
We multiply all the terms by the denominator
-2x^2*2-1x*2+3x-5*2-7*2=0
We add all the numbers together, and all the variables
-2x^2*2+3x-1x*2-24=0
Wy multiply elements
-4x^2+3x-2x-24=0
We add all the numbers together, and all the variables
-4x^2+x-24=0
a = -4; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·(-4)·(-24)
Δ = -383
Delta is less than zero, so there is no solution for the equation

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